백준
백준 14891번: 톱니바퀴
2호0
2021. 7. 2. 05:31
14891번: 톱니바퀴
첫째 줄에 1번 톱니바퀴의 상태, 둘째 줄에 2번 톱니바퀴의 상태, 셋째 줄에 3번 톱니바퀴의 상태, 넷째 줄에 4번 톱니바퀴의 상태가 주어진다. 상태는 8개의 정수로 이루어져 있고, 12시방향부터
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from collections import deque
gear1 = input()
gear1 = deque(gear1)
gear2 = input()
gear2 = deque(gear2)
gear3 = input()
gear3 = deque(gear3)
gear4 = input()
gear4 = deque(gear4)
m = []
k = int(input())
sum = 0
for i in range(k):
m.append(list(map(int, input().split())))
def c(gear):
gear.appendleft(gear[7])
gear.pop()
def rc(gear):
gear.append(gear[0])
gear.popleft()
for i in range(k):
if m[i][0]==1:
if gear1[2]!=gear2[6]:
if m[i][1]==1:
c(gear1)
if gear2[2]!=gear3[6]:
if gear3[2]!=gear4[6]:
rc(gear4)
c(gear3)
rc(gear2)
if m[i][1]==-1:
rc(gear1)
if gear2[2]!=gear3[6]:
if gear3[2]!=gear4[6]:
c(gear4)
rc(gear3)
c(gear2)
elif gear1[2]==gear2[6]:
if m[i][1]==1:
c(gear1)
if m[i][1]==-1:
rc(gear1)
if m[i][0]==2:
if gear2[2]!=gear3[6]:
if m[i][1]==1:
if gear3[2]!=gear4[6]:
c(gear4)
if gear1[2]!=gear2[6]:
rc(gear1)
c(gear2)
rc(gear3)
if m[i][1]==-1:
if gear3[2]!=gear4[6]:
rc(gear4)
if gear1[2]!=gear2[6]:
c(gear1)
rc(gear2)
c(gear3)
elif gear2[2]==gear3[6]:
if m[i][1]==1:
if gear1[2]!=gear2[6]:
rc(gear1)
c(gear2)
if m[i][1]==-1:
if gear1[2]!=gear2[6]:
c(gear1)
rc(gear2)
if m[i][0]==3:
if gear2[2]!=gear3[6]:
if m[i][1]==1:
if gear1[2]!=gear2[6]:
c(gear1)
if gear3[2]!=gear4[6]:
rc(gear4)
c(gear3)
rc(gear2)
if m[i][1]==-1:
if gear1[2]!=gear2[6]:
rc(gear1)
if gear3[2]!=gear4[6]:
c(gear4)
rc(gear3)
c(gear2)
elif gear2[2]==gear3[6]:
if m[i][1]==1:
if gear3[2]!=gear4[6]:
rc(gear4)
c(gear3)
if m[i][1]==-1:
if gear3[2]!=gear4[6]:
c(gear4)
rc(gear3)
if m[i][0]==4:
if gear3[2]!=gear4[6]:
if m[i][1]==1:
c(gear4)
if gear2[2]!=gear3[6]:
if gear1[2]!=gear2[6]:
rc(gear1)
c(gear2)
rc(gear3)
if m[i][1]==-1:
rc(gear4)
if gear2[2]!=gear3[6]:
if gear1[2]!=gear2[6]:
c(gear1)
rc(gear2)
c(gear3)
elif gear3[2]==gear4[6]:
if m[i][1]==1:
c(gear4)
if m[i][1]==-1:
rc(gear4)
if gear1[0]=='1':
sum+=1
if gear2[0]=='1':
sum+=2
if gear3[0]=='1':
sum+=4
if gear4[0]=='1':
sum+=8
print(sum)
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